What is the slope of any line perpendicular to the line passing through #(-24,19)# and #(-8,15)#?

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Answer 1 · 2016-07-22T17:54:05

Slope of desired line is #4#.

Slope of a line joining #(x_1,y_1)# and #(x_2,y_2)# is given by

#(y_2-y_1)/(x_2-x_1)#

Hence, slope the line passing through (−24,19) and (−8,15) is #(15-19)/(-8-(-24))=-4/16=-1/4#.

As product of slopes two perpendicular lines is #-1#, slope of desired line will be #(-1)/(-1/4)=-1xx-4=4#.

Answer 2 · 2016-07-22T17:54:05

Slope of desired line is #4#.

Slope of a line joining #(x_1,y_1)# and #(x_2,y_2)# is given by

#(y_2-y_1)/(x_2-x_1)#

Hence, slope the line passing through (−24,19) and (−8,15) is #(15-19)/(-8-(-24))=-4/16=-1/4#.

As product of slopes two perpendicular lines is #-1#, slope of desired line will be #(-1)/(-1/4)=-1xx-4=4#.