What is the slope of any line perpendicular to the line passing through $(-24,19)$ and $(-8,15)$ ?

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Answer 1 · 2016-07-22T17:54:05

Slope of desired line is $4$ .

Slope of a line joining $(x_1,y_1)$ and $(x_2,y_2)$ is given by

$(y_2-y_1)/(x_2-x_1)$

Hence, slope the line passing through (−24,19) and (−8,15) is $(15-19)/(-8-(-24))=-4/16=-1/4$ .

As product of slopes two perpendicular lines is $-1$ , slope of desired line will be $(-1)/(-1/4)=-1xx-4=4$ .

Answer 2 · 2016-07-22T17:54:05

Slope of desired line is $4$ .

Slope of a line joining $(x_1,y_1)$ and $(x_2,y_2)$ is given by

$(y_2-y_1)/(x_2-x_1)$

Hence, slope the line passing through (−24,19) and (−8,15) is $(15-19)/(-8-(-24))=-4/16=-1/4$ .

As product of slopes two perpendicular lines is $-1$ , slope of desired line will be $(-1)/(-1/4)=-1xx-4=4$ .

What is the slope of any line perpendicular to the line passing through (-24,19)(-24,19) and (-8,15)(-8,15)?