What is the slope of any line perpendicular to the line passing through (15,-22)(15,−22) and (12,-15)(12,−15)?

1 Answer
Jim G.
Oct 2, 2016

m=3/7m=37

Explanation:

Given 2 perpendicular lines with slopes m_1" and " m_2m1 and m2 then

color(red)(bar(ul(|color(white)(a/a)color(black)(m_1xxm_2=-1)color(white)(a/a)|)))

We require to calculate m_1 using the color(blue)"gradient formula"

color(red)(bar(ul(|color(white)(a/a)color(black)(m=(y_2-y_1)/(x_2-x_1))color(white)(a/a)|)))
where (x_1,y_1)" and " (x_2,y_2)" are 2 coordinate points"

The 2 points here are (15 ,-22) and (12 ,-15)

rArrm_1=(-15-(-22))/(12-15)=7/(-3)=-7/3

Thus -7/3xxm_2=-1

rArrm_2=(-1)/(-7/3)=3/7

Hence the slope of any line perpendicular to the line passing through the 2 given points is m=3/7

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