What is the slope-intercept form of #3x+5y=1 #?

2 Answers
Meave60
Mar 28, 2018

#3x+5y=1# in slope-intercept form is #y=-3/5x+1/5#.

Explanation:

A linear equation in slope intercept form is: #y=mx+b#. The given equation is in standard form, #Ax + Bx = C#. To convert from the standard from to the slope-intercept form, solve the standard form for #y#.

#3x+5y=1#

Subtract #3x# from both sides.

#5y=-3x+1#

Divide both sides by #5#.

#y=-3/5x+1/5#

The graph below shows the graph of both equations, which you can see is the same.

graph{(3x+5y-1)(y+3/5x-1/5)=0 [-10, 10, -5, 5]}

SuperHeroMe
Mar 28, 2018

#y = -3/5x + 1/5#

Explanation:

First subtract #3x# from both sides, and you should have #5y = -3x + 1#. You are almost there to slope-intercept form, the #5y# needs to be just #y#. Divide by 5 on both sides (Make sure you divide #-3x# AND 1 by 5!). And then you have it in slope intercept form, #y = -3/5x + 1/5# .

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