What is the slope and y-intercept of this line #y = (-4/5)x + 1#?

2 Answers
Deepak G.
Aug 13, 2016

slope#=-4/5#
#y#-intercept is #y=1#

Explanation:

#y=mx+c# where #m# is the slope
#y=(-4/5)x+1#
Hence slope#=-4/5#-------------------------Ans #1#
#y#-intercept is when #x=0#
By plugging the value #x=0# inthe equation #y=(-4/5)x+1#
we get
#y=-4/5times0+1#
or
#y=0+1#
or
#y=1#-----------------------------Ans #2#

Jim G.
Aug 13, 2016

slope = #-4/5#
y-intercept = 1

Explanation:

The equation of a line in #color(blue)"slope-intercept form"# is

#color(red)(|bar(ul(color(white)(a/a)color(black)(y=mx+b)color(white)(a/a)|)))#
where m represents the slope and b, the y-intercept.

The advantage to having the equation in this form, is that m and b may be extracted 'easily'.

The equation here #y=-4/5x+1" is in this form"#

#rArr"slope" =-4/5" and y-intercept" =1#

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