What is the slope and intercept for #y=2x+3# and how would you graph it?

2 Answers
Harish Chandra Rajpoot
Jul 26, 2018

See answers below

Explanation:

The given equation of line:

#y=2x+3#

Comparing above equation with the standard slope-intercept form #y=mx+c#, we get

Slope: #m=2#

Now, given equation can be re-written as

#2x-y=-3#

#x/{-3/2}+y/3=1#

Comparing above equation with intercept form: #x/a+y/b=1#, we get

x-intercept: #a=-3/2#

y-intercept: #b=3#

Now, the given straight line intersects the coordinate axes at #(-3/2, 0)# & #(0, 3)#. Specify these points on XY-plane & join them by a straight line to get plot.

G_Ozdilek
Jul 26, 2018

Here is the solution

Explanation:

Assign a value to x to find y value

If x is 1, #y=5#

Assign another value to x

If x is 2, #y=7#

Slope formula #=(Delta y) / (Delta x) = (7-5)/(2-1) = 2#

If x is zero #y=3#

If y is zero, #x=-3/2#

The graph is below (it is a linear function)

graph{(2x) + 3 [-8.88, 11.12, -3.96, 6.04]}

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