What is the simplest radical form of the square root of 216? Algebra Radicals and Geometry Connections Simplification of Radical Expressions 1 Answer Don't Memorise Jul 30, 2015 #=color(blue)(6sqrt(6)# Explanation: Prime factorisation of #216# helps us simplify the radical: #216=sqrt(2*2*2*3*3*3)# #=sqrt(2^2*2*3^3*3)# #=2*3sqrt(2*3)# #=color(blue)(6sqrt(6)# Answer link Related questions How do you simplify radical expressions? How do you simplify radical expressions with fractions? How do you simplify radical expressions with variables? What are radical expressions? How do you simplify #root{3}{-125}#? How do you write # ""^4sqrt(zw)# as a rational exponent? How do you simplify # ""^5sqrt(96)# How do you write # ""^9sqrt(y^3)# as a rational exponent? How do you simplify #sqrt(75a^12b^3c^5)#? How do you simplify #sqrt(50)-sqrt(2)#? See all questions in Simplification of Radical Expressions Impact of this question 18096 views around the world You can reuse this answer Creative Commons License