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What is the second derivative of #f(x)= 3x^(2/3)-x^2#?

1 Answer

Mar 8, 2017

#f''(x) = -2(1/(3x^(4/3))+1)#

Explanation:

#f(x) = 3x^(2/3)-x^2#

#f'(x) = 3* 2/3x^(2/3-1) - 2x# [Power rule]

#= 2x^(-1/3) - 2x#

#f''(x) = 2* -1/3x^(-1/3-1) -2# [Power rule]

#= -2(1/3x^(-4/3)+1)#

#= -2(1/(3x^(4/3))+1)#

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