What is the second derivative of #f(t) = (3e^-2t) - (5e^-t) #? Calculus Graphing with the Second Derivative Relationship between First and Second Derivatives of a Function 1 Answer Binayaka C. Aug 5, 2018 #(d^2y)/(dt^2) = - 5/ e^t# Explanation: #f(t) = (3 e^(-2)t) - (5 e^(-t))# or #f(t) = (3/ e^2 t) - (5 e^(-t))# or #f^'(t) = (3/ e^2 ) - (5 e^(-t)*(-1))# or #f^'(t) = (3/ e^2 ) + (5 e^(-t))# or #(d^2y)/(dt^2) = 0 + (5 e^(-t)*(-1))# or #(d^2y)/(dt^2) = - (5 e^(-t))# or #(d^2y)/(dt^2) = - 5/ e^t# [Ans] Answer link Related questions What is the relationship between the First and Second Derivatives of a Function? Question #64fc4 What are the first two derivatives of #y = 2sin(3x) - 5sin(6x)#? What is the second derivative of the function #f(x)=sec x#? If #f(x)=sec(x)#, how do I find #f''(π/4)#? What is the second derivative of #g(x) = sec(3x+1)#? How do you use the second derivative test to find the local maximum and minimum for... What is the first and second derivative of #1/(x^2-x+2)#? What is the second derivative of #x/(x-1)# and the first derivative of #2/x#? What does the 2nd Derivative Test tell you about the behavior of #f(x) = x^4(x-1)^3# at these... See all questions in Relationship between First and Second Derivatives of a Function Impact of this question 2127 views around the world You can reuse this answer Creative Commons License