What is the relationship between the pOH and the OH- ion concentration of a solution?

1 Answer
anor277
Dec 16, 2016

pOH=-log_10[HO^-]

Explanation:

And in aqueous solution, the acid base equilibrium operates:

2H_2OrightleftharpoonsH_3O^(+) + HO^-

At 298*K, K_w=10^-14=[HO^-][H_3O^+]

And taking negative log_10 of both sides.............

-log_10K_w=-log_(10)10^-14=-log_10[HO^-]-log_10[H_3O^+]

i.e. 14=pH+pOH.

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