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What is the ratio of the measure of the complement of a 50 degrees-angle to the measure of the supplement of the same angle?

1 Answer

Jun 15, 2015

$\frac{complement 50^{\circ}}{supplement 50^{\circ}} = \frac{4}{13}$ $("complement "50^@)/("supplement " 50^@) = 4/13$

Explanation:

By definition the complement of an angle is $90^{\circ}$ $90^@$ minus the angle
and the supplement of an angle is $180^{\circ}$ $180^@$ minus the angle.

The complement of $50^{\circ}$ $50^@$ is $40^{\circ}$ $40^@$
The supplement of $50^{\circ}$ $50^@$ is $130^{\circ}$ $130^@$

The ratio $\frac{complement 50^{\circ}}{supplement 50^{\circ}}$ $("complement "50^@)/("supplement " 50^@)$

$XXXX$ $color(white)("XXXX")$ $= \frac{40^{\circ}}{130^{\circ}} = \frac{4}{13}$ $=(40^@)/(130^@) = 4/13$

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