What is the projection of <7,-8,3 > onto <5,-6,1 >?

1 Answer
Feb 19, 2017

The vector projection is =43/31<5,-6,1>
The scalar projection is =86/sqrt62

Explanation:

The vector projection of vecb onto veca is

=(veca.vecb)/(|veca|^2)*veca

The dot product is

veca.vecb=<5,-6,1>*<7,-8,3>

=5*7+(-6*-8)+3*1

=35+48+3

=86

The modulus of veca is

||veca||=||<5,-6,1>||

=sqrt(25+36+1)

=sqrt62

The vector projection is

=86/62*<5,-6,1>

=43/31<5,-6,1>

The scalar projection is

=(veca.vecb)/(||veca||)

=86/sqrt62