What is the projection of #<-6,3,2 ># onto #<1,4,-3 >#?

1 Answer
Narad T.
Jan 9, 2017

No projection possible

Explanation:

The vector projection of #vecb# over #veca# is

#=(veca.vecb)/(∥veca∥^2)veca#

The dot product is #veca.vecb=〈-6,3,2〉.〈1,4,-3〉=-6+12-6=0#

The vectors #veca# and #vecb# are perpendicular, it's not possible to make a projection.

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