What is the projection of <4,-1,6 > onto <1,3,-2 >?

1 Answer
Sep 16, 2016

= - (11)/sqrt(14)

Explanation:

well you start with the scalar dot product

vec A * vec B = abs vec A abs vec B cos phi, where phi is the angle between the vectors

then you insist that vec B be the unit vector hat B = (vec B)/(abs vec B) so that

abs hat B = 1

and

vec A * hat B = abs vec A (1) cos phi = abs vec A cos phi which is the length of vec A in the \hat B direction

so that we can actually say that

(vec A * (vec B)/(abs vec B) = vec A * hat B = abs vec A cos phi )\ hat B

so with vec A = <4,-1,6 >

and vec B = <1,3,-2 > meaning hat B = 1/sqrt(14) <1,3,-2 >

(vec A * hat B = 1/sqrt(14) ( <4,-1,6 > * <1,3,-2 > ) )hat B

= 1/sqrt(14) (4 - 3 - 12 ) hat B

= - (11)/sqrt(14) hat B