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What is the polar form of #(1-,18)#?

1 Answer

sankarankalyanam

Jul 9, 2018

#color(cyan)("Polar Form " (r, theta) = (sqrt 325, 356.82^@)#

Explanation:

#"Given : " x = 1, y = -18#

#r = sqrt(x^2 + y^2) = sqrt(-1^2 + 18^2) = sqrt 325#

#theta = arctan (y/x) = arctan (-1/18) = 356.82^@, " IV Quadrant"#

#color(cyan)("Polar Form " (r, theta) = (sqrt 325, 356.82^@)#

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