What is the period of #y=cos(1/3theta)#?

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What is the period of #y=cos(1/3theta)#?

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Answer 1 · 2017-01-04T21:55:01

For the general form, #y = (A)cos(Btheta + C) + D#, the period is, #T = (2pi)/B#
For the given equation, #y = cos(1/3theta)#, the period is #T = (2pi)/(1/3) = 6pi#

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What is the period of #y=cos(1/3theta)#?

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