What is the period of #f(theta)= sin 2 t - cos 5 t #?

1 Answer
A. S. Adikesavan
Apr 8, 2016

#2pi#

Explanation:

The period for #sin kt = 2pi/k#.

The separate periods for sin 2t and sin 5t are #pi# and the smaller #2pi/5#. Match with suitable integer multiples m and n such that #m=2n/5#. .
The least common multiple period is #2pi#, for m=2 and n=5. .

So, this is the period for the compounded oscillation.
#f(t)=sin 2t-sin 5t#.

The laast value of P for which f(t+P)=f(t) is #2pi#.

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