What is the period of #f(t)=sin( ( 11t) /6 )#?
1 Answer
Mar 12, 2016
Explanation:
for the function y = a sin(bx + c)
the amplitude = |a| , period =
#(2pi)/b" and c is phase shift "# here b =
#11/6 rArr " period " = (2pi)/(11/6) = (12pi)/11 #
