What is the percent yield of the following reaction if 60 grams of CaCO3 is heated to give 15 grams of CaO? CaCO3→CaO + CO2

Question

What is the percent yield of the following reaction if 60 grams of CaCO3 is heated to give 15 grams of CaO? CaCO3→CaO + CO2

1 Answer

Impact of this question

78271 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2014-09-18T21:23:22

The percent yield is 45 %.

CaCO₃ →CaO + CO₂

First, calculate the theoretical yield of CaO.

Theor. yield = ${60 g CaCO}_{3} \times \frac{{1 mol CaCO}_{3}}{{100.0 g CaCO}_{3}} \times \frac{1 mol CaO}{{1 mol CaCO}_{3}} \times \frac{56.08 g CaO}{1 mol CaO} = 33.6 g CaO$ $"60 g CaCO"_3 × ("1 mol CaCO"_3)/("100.0 g CaCO"_3) × "1 mol CaO"/("1 mol CaCO"_3) × "56.08 g CaO"/"1 mol CaO" = "33.6 g CaO"$

Now calculate the percent yield.

% yield = $\frac{actual yield}{theoretical yield} \times 100 % = \frac{15 g}{33.6 g} \times 100 % = 45 %$ $"actual yield"/"theoretical yield" × 100 % = "15 g"/"33.6 g" × 100 % = 45 %$

www.chem.arizona.edu

Science

Math

Humanities

... and beyond

What is the percent yield of the following reaction if 60 grams of CaCO3 is heated to give 15 grams of CaO? CaCO3→CaO + CO2

1 Answer

Related questions

Impact of this question