What is the percent composition of each element in vitamin E, C_29H_50O_2?

1 Answer
Ernest Z.
Mar 7, 2016

The composition of Vitamin E is "80.87 % C, 11.70 % H", and "7.43 % O".

Explanation:

We can calculate the molecular mass of Vitamin C as follows:

29 color(red)(cancel(color(black)("atoms C"))) × "12.01 u"/(1 color(red)(cancel(color(black)("atom C")))) = "348.29 u"
50 color(red)(cancel(color(black)("atoms H"))) × "1.008 u"/(1 color(red)(cancel(color(black)("atom H")))) = "50.40 u"
2 color(red)(cancel(color(black)("atoms O"))) × "16.00 u"/(1 color(red)(cancel(color(black)("atom O")))) =color(white)(l) "32.00 u"
"TOTAL"color(white)(mmmmmmmm) = "430.69 u"

The mass percentages of each element are:

"% C" = (348.29 color(red)(cancel(color(black)("u"))))/(430.69 color(red)(cancel(color(black)("u")))) × 100 % = 80.87 %
"% H" = (50.40 color(red)(cancel(color(black)("u"))))/(430.69 color(red)(cancel(color(black)("u")))) × 100 % = 11.70 %
"% O" = (32.00 color(red)(cancel(color(black)("u"))))/(430.69 color(red)(cancel(color(black)("u")))) × 100 % =color(white)(ll) 7.43 %

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