What is the ordered pairs that satisfy the equation 3x - 2y = 63x−2y=6?

1 Answer
Ms. Worth
Nov 25, 2017

You can find as many ordered pairs as you want.

Here are some:
(6,6)(6,6)
(2,0)(2,0)larr← This is the xx intercept
(0,- 3)(0,−3)larr← This is the yy intercept
(-2,-6)(−2,−6)
(-6,-12)(−6,−12)

Explanation:

You can write this line in slope-intercept form and use that equation to generate as many ordered pairs as you want.

3x - 2y = 63x−2y=6
Solve for yy

1) Subtract 3x3x from both sides to isolate the -2y−2y term
-2y = -3x + 6−2y=−3x+6

2) Divide both sides by - 2−2 to isolate yy
y = (3x)/(2) - 3y=3x2−3

Now assign various values to xx and solve for yy to generate as many ordered pairs as you want.

Hot tip: Since you'll be dividing 3x3x by 22, choose only even numbers for xx

... xx .... | ... yy ... | . .Ordered Pairs
.............|.............|...................................
... 66 ......| .... 66 ...| . . . (6,6)(6,6)
... 22 ......| .... 00 ...| . . . (2,0)(2,0)larr← This is the xx intercept
... 00 ......|. -3−3 ...| . . . (0,⎯ 3)larr← This is the yy intercept
-2−2 ......|. -6−6 ...| . . . (⎯ 2,⎯ 6)
-6 ......|. -12 .| . . . (⎯ 6,⎯ 12)

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