What is the norm of $< 8 ,-2 , 5 >$ ?

Question

1220 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-01-27T07:35:21

$abs( abs(< 8, -2, 5 >) ) = sqrt(93) ~~ 9.643650761$

In general:

$abs( abs(< a, b, c >) ) = sqrt(a^2+b^2+c^2)$

So in our example:

$abs( abs(< 8, -2, 5 >) ) = sqrt(8^2+(-2)^2+5^2)$

$=sqrt(64+4+25) = sqrt(93) ~~ 9.643650761$

What is the norm of < 8 ,-2 , 5 >< 8 ,-2 , 5 >?