What is the norm of #< 8 ,-2 , 5 >#?
1 Answer
Jan 27, 2016
#abs( abs(< 8, -2, 5 >) ) = sqrt(93) ~~ 9.643650761#
Explanation:
In general:
#abs( abs(< a, b, c >) ) = sqrt(a^2+b^2+c^2)#
So in our example:
#abs( abs(< 8, -2, 5 >) ) = sqrt(8^2+(-2)^2+5^2)#
#=sqrt(64+4+25) = sqrt(93) ~~ 9.643650761#
