What is the norm of $< -5 , 4 , 5 >$ ?

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Answer 1 · 2018-04-10T12:46:19

$sqrt 66$

The standard (Euclidean) norm of a vector $vec a = (a_1,a_2,a_3)$ is

$||vec a|| =sqrt(a_1^2+a_2^2+a_3^2)$

So, for the given vector, the norm is

$sqrt((-5)^2+4^2+5^2) = sqrt 66$

What is the norm of < -5 , 4 , 5 >< -5 , 4 , 5 >?