What is the norm of < -5 , -2, 4 >?

1 Answer
Dec 21, 2015

sqrt(45)

Explanation:

We're basically calculating the norm of the vector OA = (-5,-2,4). So we apply the formula for any M(x,y,z) in RR^3 : ||OM|| = sqrt(x^2 + y^2 + z^2).

Here, ||OA|| = sqrt((-5)^2 + (-2)^2 + 4^2) = sqrt(25 + 4 + 16) = sqrt(45)