What is the norm of $< -5 , -2, -1 >$ ?

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Answer 1 · 2015-12-25T16:00:37

$sqrt30$

By definition, for any n-dimensional vector $A=(a_1,a_2,a_3,......,a_n)$ , the norm is defined by
$||A||=sqrt(a_1^2+a_2^2+a_3^2+........+a_n^2)$ .

So in this particular case we have a 3 dimensional vector (n = 3), and so its norm is given by

$||(-5,-2,-1)||=sqrt((-5)^2+(-2)^2+(-1)^2)$

$=sqrt30$

What is the norm of < -5 , -2, -1 >< -5 , -2, -1 >?