What is the norm of $< - 3, - 1, 8 >$ $< -3, -1 , 8 >$ ?

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Answer 1 · 2016-01-18T13:05:44

$\sqrt{74}$ $sqrt74$

For any vector $A=(a_1,a_2,....,a_n)$ in any finite n-dimensional vector space, the norm is defined as follows :

$||A||=sqrt(a_1^2+a_2^2+....+a_n^2)$ .

So in this particular case we work in $RR^3$ and get :

$||((-3,-1,8))||=sqrt(3^2+1^2+8^2)=sqrt74$ .

What is the norm of < -3, -1 , 8 ><−3,−1,8>< -3, -1 , 8 >?