What is the norm of < -3, -1 , -3 >?

1 Answer
David G.
Feb 2, 2016

The norm is otherwise described as the normalized version of a vector: a unit vector in the same direction as the original vector. In this case: <-3/sqrt19,-1/sqrt19,-3/sqrt19>.

Explanation:

We need to find the length of the initial vector. For a vector <a, b, c>

l = sqrt(a^2+b^2+c^2) = sqrt((-3)^2+(-1)^2+(-3)^2) = sqrt(9+1+9) = sqrt 18

Then we simply divide each of the 3 elements by this length to yield a unit vector: <-3/sqrt19,-1/sqrt19,-3/sqrt19>.

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