What is the mole fraction of $KI$ in a solution made by dissolving 3.4 g of $KI$ in 5.8 g of water?

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Answer 1 · 2017-01-05T16:24:59

$"Mole fraction"$ $=$ $"Moles of component"/"Moles of all species in solution"$

And thus, $"Mole fraction, KI"$ $=$ $"Moles of KI"/"Moles of KI + moles of water"$

$=((3.4*g)/(166.00*g*mol^-1))/((3.4*g)/(166.00*g*mol^-1)+(5.8*g)/(18.01*g*mol^-1))$ $=$ $0.060$

Note that the mole fraction of $"water"$ here must be necessarily $1-0.060=0.94$ . Why $"necessarily"$ ?

Note that $"mole fractions"$ , as they are here, are dimensionless quantities.

What is the mole fraction of KIKI in a solution made by dissolving 3.4 g of KIKI in 5.8 g of water?