What is the mole fraction of KI in a solution made by dissolving 3.4 g of KI in 5.8 g of water?

1 Answer
Jan 5, 2017

"Mole fraction" = "Moles of component"/"Moles of all species in solution"

Explanation:

And thus, "Mole fraction, KI" = "Moles of KI"/"Moles of KI + moles of water"

=((3.4*g)/(166.00*g*mol^-1))/((3.4*g)/(166.00*g*mol^-1)+(5.8*g)/(18.01*g*mol^-1)) = 0.060

Note that the mole fraction of "water" here must be necessarily 1-0.060=0.94. Why "necessarily"?

Note that "mole fractions", as they are here, are dimensionless quantities.