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What is the molarity of a solution with 73 g of #HCl# in 319 mL of solution?

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1 Answer

May 20, 2016

Approx. #6.5*mol*L^-1# with respect to hydrochloric acid.

Explanation:

#"Molarity"# #=# #"Moles of solute"/"Volume of solution"#

#=# #(73*g)/(35.45*g*mol^-1)xx1/(0.319*L)# #=# #??*mol*L^-1#.

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