What is the molarity of a solution with 73 g of $HCl$ in 319 mL of solution?

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Answer 1 · 2016-05-20T18:44:06

Approx. $6.5*mol*L^-1$ with respect to hydrochloric acid.

$"Molarity"$ $=$ $"Moles of solute"/"Volume of solution"$

$=$ $(73*g)/(35.45*g*mol^-1)xx1/(0.319*L)$ $=$ $??*mol*L^-1$ .

What is the molarity of a solution with 73 g of HClHCl in 319 mL of solution?