What is the molarity of a solution that contains 50.0 g of $Mg(NO_3)_2$ per 225 mL of solution?

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Answer 1 · 2016-07-04T00:14:18

$1.50 M$

To find the molarity, the following equation must be used:

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We are given the mass and volume of the solution, but both have bad units.

The mass of $Mg(NO_3)_2$ can be converted into moles by using its molar mass (148.3 g/mol) as a conversion factor:

$50.0cancelgxx(1mol)/(148.3cancelg)$ $=0.337 mol$

Now we can convert 225 mL into L by multiplying 225 by 0.001 to obtain 0.225L.

All we do now is divide the number of moles by the volume to acquire the molarity:

$M = (0.337 mol) / (0.225 L)$ = 1.50 M

What is the molarity of a solution that contains 50.0 g of Mg(NO_3)_2Mg(NO_3)_2 per 225 mL of solution?