What is the molarity of a solution of $NaOH$ if 2 liters of the solution contains 4 moles of $NaOH$ ?

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Answer 1 · 2016-04-30T20:00:10

$2$ $mol*L^-1$ with respect to $NaOH$ .

$"Concentration"$ $=$ $"Moles of solute"/"Volume of solution"$

$=$ $(4*mol" Sodium hydroxide")/(2*L" of solution")$

$=$ $2*mol*L^-1$

What is the molarity of a solution of NaOHNaOH if 2 liters of the solution contains 4 moles of NaOHNaOH?