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What is the molarity of a solution in which there are 25 gms of #Na_2SO_4# in 500 mL solution?

1 Answer

Feb 2, 2017

#"Molarity"~=0.4*mol*L^-1# with respect to sodium sulfate.

Explanation:

#"Concentration, molarity"# #=# #"Moles of solute"/"Volume of solution"#.

And thus we set up the quotient:

#((25*cancelg)/(142.0*cancelg*mol^-1))/(500*cancel(mL)xx10^-3*L*cancel(mL^-1))=??*mol*L^-1#

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