What is the molarity of a solution in which there are 25 gms of $Na_2SO_4$ in 500 mL solution?

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Answer 1 · 2017-02-02T08:52:15

$"Molarity"~=0.4*mol*L^-1$ with respect to sodium sulfate.

$"Concentration, molarity"$ $=$ $"Moles of solute"/"Volume of solution"$ .

And thus we set up the quotient:

$((25*cancelg)/(142.0*cancelg*mol^-1))/(500*cancel(mL)xx10^-3*L*cancel(mL^-1))=??*mol*L^-1$

What is the molarity of a solution in which there are 25 gms of Na_2SO_4Na_2SO_4 in 500 mL solution?