What is the molarity of a solution in which 58 g of $N a C l$ $NaCl$ are dissolved in 1.0 L of solution?

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What is the molarity of a solution in which 58 g of $N a C l$ $NaCl$ are dissolved in 1.0 L of solution?

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Answer 1 · 2016-04-13T19:14:44

A tad under $1$ $1$ $m o l \cdot L^{- 1}$ $mol*L^-1$ .

Explanation:

Sodium chloride has an equivalent mass of $58.44 \cdot g \cdot m o l^{- 1}$ $58.44*g*mol^-1$ .

Since $Molarity$ $"Molarity"$ $=$ $=$ $\frac{Moles of solute (mol)}{Volume of solution (L)}$ $"Moles of solute (mol)"/"Volume of solution (L)"$ , the concentration of sodium chloride $=$ $=$ $\frac{58 \cdot g}{58.44 \cdot g \cdot m o l^{- 1}} \times \frac{1}{1.0 \cdot L}$ $(58*g)/(58.44*g*mol^-1)xx1/(1.0*L)$ $=$ $=$ $? ?$ $??$ $m o l \cdot L^{- 1}$ $mol*L^-1$

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What is the molarity of a solution in which 58 g of $N a C l$ $NaCl$ are dissolved in 1.0 L of solution?

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What is the molarity of a solution in which 58 g of NaClNaClNaCl are dissolved in 1.0 L of solution?

1 Answer

Explanation:

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What is the molarity of a solution in which 58 g of $N a C l$ $NaCl$ are dissolved in 1.0 L of solution?