What is the molarity of a NaOH solution if 28.50 mL are needed to titrated a 0.7154 g sample of KHP?

1 Answer
anor277
Nov 23, 2017

#1,2-C_6H_4(CO_2H)(CO_2^(-)K^(+))+NaOH(aq) rarr C_6H_4(CO_2^(-)Na^(+))(CO_2^(-)K^(+)) + H_2O(l)#

Explanation:

And thus the moles of #KHP# is equivalent to the moles of sodium hydroxide, the which are dissolved in a volume of #28.50*mol#.

#((0.7154*g)/(204.22*g*mol^-1))/(28.50xx10^-3*L)=0.1229*mol*L^-1#

..........WITH RESPECT TO #NaOH(aq)#....

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