What is the molarity of 416.48 g #BaCl_2# dissolved in #2# #L# of water?

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Answer 1 · 2016-04-11T05:42:02

1 mol / L

Molarity = # of moles of solute/ Volume of solution in ( liter)

Number of moles of Ba#Cl_2# =
mass of Ba#Cl_2# dissolved/ molar mass of Ba#Cl_2#

mass of Ba#Cl_2# dissolved = 416.48 g

molar mass of Ba#Cl_2# = 208.23 g/mol

Number of moles of Ba#Cl_2# = 416.48 g / 208.23 g /mol = 2 mol

Molarity = # of moles of solute/ Volume of solution in ( liter)

           =   2 moles / 2 L

           = 1 mol /L