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What is the molarity of 40.0 grams of sodium hydroxide in 1.50 L of solution?

1 Answer

Mar 29, 2016

#"Molarity"# #=# #"Amount of substance (in moles)"/"Volume of solution (in litres)"#

Explanation:

So, #(40.0*cancelg)/(40*cancelg*mol^-1)/(1.50*L)# #=# #0.667# #mol*L^-1# with respect to sodium hydroxide.

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