What is the molarity of 40.0 grams of sodium hydroxide in 1.50 L of solution?

1 Answer
Mar 29, 2016

"Molarity" = "Amount of substance (in moles)"/"Volume of solution (in litres)"

Explanation:

So, (40.0*cancelg)/(40*cancelg*mol^-1)/(1.50*L) = 0.667 mol*L^-1 with respect to sodium hydroxide.