What is the molarity of .289 moles of $FeCl_3$ dissolved in 120 mL of solution?

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Answer 1 · 2017-12-31T03:44:14

Molarity= $(2.41"mol")/L$

Molarity= $"Moles of solute"/"Liters of solution"$

Moles= $0.289$

Solution= $120mL=0.12L$

Therefore,

Molarity= $(0.289 "mol")/(0.12 L)~~(2.41 "mol")/L$

What is the molarity of .289 moles of FeCl_3FeCl_3 dissolved in 120 mL of solution?