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What is the molarity of 10.0 g of #KCI# in 0.500 L of solution?

1 Answer

Sep 9, 2016

#"Molarity"##approx 0.25*mol*L^-1# with respect to potassium chloride.

Explanation:

#"Molarity"# #=# #"Moles of solute"/"Volume of solution"#

#=# #(10.0*g)/(74.55*g*mol^-1)xx1/(0.500*L)# #=# #??*mol*L^-1.#

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