What is the molarity of 1.5 liters of an aqueous solution that contains 52 grams of lithium fluoride, LiF?

1 Answer
anor277
Mar 12, 2017

"Molarity" = "Moles of solute"/"Volume of solution"

Explanation:

And thus, here, "Molarity" = ((52*cancelg)/(25.9*cancelg*mol^-1))/(1.5*L)=1.3*mol*L^-1, with respect to lithium fluoride

Now it is a fact that this solution would have a pH>7. Given that HF(aq) is a fairly weak acid, why should this be so?

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