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What is the molarity of 0.080 moles #NaHCO_3# in 1250 mL of solution?

1 Answer

May 10, 2016

#"Molarity = 0.064"*mol*L^-1#

Explanation:

#"Molarity"# #=# #"Amount of substance (moles)"/"Volume of solution (L)"#

#=# #(0.080*mol)/(1.250*L)# #=# #0.064"*mol*L^-1# with respect to sodium bicarbonate.

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