What is the molality of a solution containing 18 grams of solute in in 0.5 kg of solvent?

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What is the molality of a solution containing 18 grams of solute in in 0.5 kg of solvent?

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Answer 1 · 2017-04-17T14:52:47

Unknown............

Explanation:

$Molality = \frac{Moles of solute}{Kilograms of solvent}$ $"Molality"="Moles of solute"/"Kilograms of solvent"$ .

We have the mass of the solute. We do not know what it is and thus we cannot calculate its molar quantity, and thereby its molal concentration remains inaccessible.

$Molality = \frac{\frac{18 \cdot g}{Molar mass of solute}}{0.5 \cdot k g} = ? ? \cdot m o l \cdot k g^{- 1}$ $"Molality"=((18*g)/("Molar mass of solute"))/(0.5*kg)=??*mol*kg^-1$ .

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What is the molality of a solution containing 18 grams of solute in in 0.5 kg of solvent?

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