What is the mean, median, and mode for 3.56,4.40,6.25,1.20,8.52,1.20?

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Answer 1 · 2018-07-14T06:15:04

Mean = $4 \frac{113}{600}$ $4 113/600$
Median = $3.98$ $3.98$
Mode = $1.20$ $1.20$

Mean is the average of the numbers

$mean = \frac{3.56 + 4.4 + 6.25 + 1.2 + 8.52 + 1.2}{6}$ $"mean"=(3.56+4.4+6.25+1.2+8.52+1.2)/6$

$mean = 4 \frac{113}{600}$ $"mean"=4 113/600$

Median is the "middle" number when you place your numbers in ascending order

$1.20, 1.20, 3.56, 4.40, 6.25, 8.52$ $1.20,1.20,3.56,4.40,6.25,8.52$

Since there are 6 numbers, then the "middle number" is the average of your 3rd and 4th number

$median = \frac{3.56 + 4.40}{2} = 3.98$ $"median"=(3.56+4.40)/2=3.98$

Mode is the number that occurs the most which in this case is $1.20$ $1.20$ since it occurs twice