What is the limit as x approaches infinity of (x^2-4)/(2x-4x^2)?

2 Answers
Jim G.
Mar 22, 2018

-1/4

Explanation:

"divide terms on numerator/denominator by the highest"
"power of x, that is "x^2

rArr(x^2/x^2-4/x^2)/((2x)/x^2-(4x^2)/x^2)=(1-4/x^2)/(2/x-4)

rArrlim_(xtooo)(x^2-4)/(2x-4x^2)

=lim_(xtooo)(1-4/x^2)/(2/x-4)

=(1-0)/(0-4)=-1/4

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