How do I find the limit as #x# approaches infinity of #(1.001)^x#?

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Answer 1 · 2015-02-16T13:54:55

First of all the first thing we have to know is: which #oo#?

Every number #0<b<1# elevated to #+oo# is equal to #0^+# and elevated to #-oo# is equal to #+oo#.

I.E. #y=2^x#.

graph{2^x [-10, 10, -5, 5]}

Every number #b>1# elevated to #+oo# is equal to #+oo# and elevated to #-oo# is equal to #o^+#.

I.E. #y=(1/2)^x#.

graph{(1/2)^x [-10, 10, -5, 5]}