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What is the integral of #int tan^2(3x)dx#?

1 Answer

Jan 17, 2016

#int tan^2(3x) dx = 1/3 tan(3x) - x + C#

where #C# is the constant of integration

Explanation:

You should know the identity #tan^2theta-=sec^2theta-1#.

#int tan^2(3x) dx = int (sec^2(3x)-1) dx#

#= 1/3 tan(3x) - x + C#

where #C# is the constant of integration.

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