What is the integral of #(cos^2x) / sinx#? Calculus Introduction to Integration Integrals of Trigonometric Functions 1 Answer ali ergin Mar 29, 2016 #int cos^2/sin x d x=l n(tan(x/2))+cos x+C# Explanation: #int cos^2/sin x d x= ?# #cos^2 x=1-sin^2x# #int(1-sin^2 x)/(sin x) d x=int (1/sin x-sin x)d x # #int cos^2/sin x d x=int (d x)/sin x- int sin x d x# #int cos^2/sin x d x=l n(tan(x/2))+cos x+C# Answer link Related questions How do I evaluate the indefinite integral #intsin^3(x)*cos^2(x)dx# ? How do I evaluate the indefinite integral #intsin^6(x)*cos^3(x)dx# ? How do I evaluate the indefinite integral #intcos^5(x)dx# ? How do I evaluate the indefinite integral #intsin^2(2t)dt# ? How do I evaluate the indefinite integral #int(1+cos(x))^2dx# ? How do I evaluate the indefinite integral #intsec^2(x)*tan(x)dx# ? How do I evaluate the indefinite integral #intcot^5(x)*sin^4(x)dx# ? How do I evaluate the indefinite integral #inttan^2(x)dx# ? How do I evaluate the indefinite integral #int(tan^2(x)+tan^4(x))^2dx# ? How do I evaluate the indefinite integral #intx*sin(x)*tan(x)dx# ? See all questions in Integrals of Trigonometric Functions Impact of this question 30814 views around the world You can reuse this answer Creative Commons License