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What is the integral of #cos^2(6x) dx#?

1 Answer

Jun 20, 2016

#:. intcos^2(6x)dx=(1/2)(x+(sin12x)/12)+C.#

Explanation:

Recall that #cos^2theta=(1+cos2theta)/2.#

#:. cos^2(6x)=(1+cos12x)/2.#

#:. intcos^2(6x)dx=int(1+cos12x)/2dx=(1/2){x+(sin12x)/12}+C.#

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