What is the instantaneous rate of change of $f(x)=x-e^(5x-7)$ at $x=0$ ?

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Answer 1 · 2016-01-28T22:11:26

$0.99544$

This is equivalent to asking us to find the value of the derivative of the function at $x=0$ .

$therefore f'(x)=1-5e^(5x-7)$

$therefore f'(0)=1-5e^(-7)$

$=0.99544$

What is the instantaneous rate of change of f(x)=x-e^(5x-7) f(x)=x-e^(5x-7) at x=0 x=0 ?