How do you find the instantaneous rate of change of $f(t)=(2t^3-3t+4)$ when $t=2$ ?

Question

13906 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2014-09-11T14:24:17

The instantaneous rate of change can be found by
$f'(2)=21$ .

By taking the derivative,
$f(t)=6t^2-3$
By pluging in $t=2$ ,
$f'(2)=6(2)^2-3=21$

How do you find the instantaneous rate of change of f(t)=(2t^3-3t+4)f(t)=(2t^3-3t+4) when t=2t=2?