What is the instantaneous rate of change of $f(x)=(x^2-2)e^(x)$ at $x=2$ ?

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Answer 1 · 2016-01-29T17:38:43

I found $44.334$

The instantaneous rate of change is the derivative of our function (which is the rate of change) evaluated at the specific point (at $x=2$ ).

So we get:

$f'(x)=(2x)e^x+(x^2-2)e^x$ using the Product Rule.

Evaluate it at $x=2$ to get:

$f'(2)=4e^2+2e^2=6e^2=44.334$

What is the instantaneous rate of change of f(x)=(x^2-2)e^(x) f(x)=(x^2-2)e^(x) at x=2 x=2 ?