What is the instantaneous rate of change of $f(x)=(x-1)^2-4x$ at $x=0$ ?

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Answer 1 · 2016-11-07T04:01:55

Instantaneous rate of change at x=0 of f(x) is -6.

$f(x)=(x-1)^2-4x$
$f(x)=x^2-2x+1-4x$
$f(x)=x^2-6x+1$

Use power rule to find $f'(x)$ :
$f'(x)=2x-6$
$f'(0)=2(0)-6=-6$

$f'(0)=-6$

What is the instantaneous rate of change of f(x)=(x-1)^2-4xf(x)=(x-1)^2-4x at x=0x=0?